Декодирование массива в модели Swift (декодируемый)

import Foundation

let string =  """
{
    "id": "xxxxxx",
    "result": [
        [
            "client_id",
            "name",
            50,
            "status"
        ]
    ],
    "error": null
}
"""

struct Container: Codable {
    let id: String
    let result: [[Result]]
    let error: String?
}

enum Result: Codable {
    case integer(Int)
    case string(String)

    init(from decoder: Decoder) throws {
        let container = try decoder.singleValueContainer()
        if let x = try? container.decode(Int.self) {
            self = .integer(x)
            return
        }
        if let x = try? container.decode(String.self) {
            self = .string(x)
            return
        }
        throw DecodingError.typeMismatch(Result.self, DecodingError.Context(codingPath: decoder.codingPath, debugDescription: "Wrong type for Result"))
    }

    func encode(to encoder: Encoder) throws {
        var container = encoder.singleValueContainer()
        try container.encode(self)
    }
}

let jsonData = string.data(using: .utf8)!
let container = try? JSONDecoder().decode(Container.self, from: jsonData)

print(container)

улучшенный ответ @ArinDavoodian.

Чтобы прочитать данные:

container?.result.first?.forEach { object in
    switch object {
    case let .integer(intValue):
        print(intValue)
        break
    case let .string(stringValue):
        print(stringValue)
        break
    }
}

простое решение:

let yourInsideArray = container?.result.first!
for index in 0..<yourInsideArray.count {
let yourObjectInsideThisArray = yourInsideArray[i]
//do some
 switch yourObjectInsideThisArray {
    case let .integer(intValue):
        print(intValue)
        break
    case let .string(stringValue):
        print(stringValue)
        break
    }
}